4x^2-160x+1600=1296

Solution for 4x^2-160x+1600=1296 equation:

4x^2-160x+1600=1296

We move all terms to the left:

4x^2-160x+1600-(1296)=0

We add all the numbers together, and all the variables

4x^2-160x+304=0

a = 4; b = -160; c = +304;
Δ = b2-4ac
Δ = -1602-4·4·304
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-144}{2*4}=\frac{16}{8}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+144}{2*4}=\frac{304}{8}
=38
$